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13x^2+21x-5=0
a = 13; b = 21; c = -5;
Δ = b2-4ac
Δ = 212-4·13·(-5)
Δ = 701
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{701}}{2*13}=\frac{-21-\sqrt{701}}{26} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{701}}{2*13}=\frac{-21+\sqrt{701}}{26} $
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